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(B) Dispersive power $(\omega)$ is defined as the ratio of angular dispersion to the mean deviation.Mathematically, $\omega = \frac{\delta_2 - \delta_

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(B) Dispersive power $(\omega)$ is defined as the ratio of angular dispersion to the mean deviation.Mathematically, $\omega = \frac{\delta_2 - \delta_1}{\delta_{avg}}$, where $\delta_2$ and $\delta_1$ are the deviations of the extreme wavelengths and $\delta_{avg}$ is the deviation of the mean wavelength.Visually, the dispersive power is proportional to the angular spread between the extreme rays ($\lambda_1$ and $\lambda_2$) relative to the deviation of the mean ray $(\lambda_{avg})$.In diagram $B$, the angular separation between the rays corresponding to $\lambda_1$ and $\lambda_2$ is the largest relative to the deviation of the mean ray $\lambda_{avg}$.Therefore, diagram $B$ represents the case with the maximum dispersive power.

Consider the four different cases of dispersion of a light ray which has all the wavelengths from ${\lambda _1}$ to ${\lambda _2}$ (where ${\lambda _1} > {\lambda _2}$). The dotted line represents the light ray of wavelength ${\lambda _{avg}}$. Which ray diagram shows the maximum dispersive power?

Similar Questions

Dispersive power depends on the following:

If the refractive indices of a prism for red,yellow,and violet colours are $1.61$,$1.63$,and $1.65$ respectively,then the dispersive power of the prism will be:

The refractive index of flint glass for blue light is $1.6333$ and for red light is $1.6161$. Calculate the dispersive power of the prism,assuming the mean refractive index is approximately the average of the two given values.

Mention the constituent colors of white light.

Explain the refractive index for light of different colours.

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